How do you solve #5x + 12\geq - 7x#?

1 Answer
Jim G.
Dec 23, 2016

#x>= -1#

Explanation:

Collect terms in x on one side of the inequality and numeric values on the other side.

add 7x to both sides.

#5x+7x+12>= cancel(-7x)cancel(+7x)#

#rArr12x+12>=0#

subtract 12 from both sides.

#12xcancel(+12)cancel(-12)>=0-12#

#rArr12x>= -12#

To solve for x, divide both sides by 12

#(cancel(12) x)/cancel(12)>= (-12)/12#

#rArrx>= -1" is the solution"#

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