How do you solve #5x + 12\geq - 7x#?
1 Answer
Dec 23, 2016
Explanation:
Collect terms in x on one side of the inequality and numeric values on the other side.
add 7x to both sides.
#5x+7x+12>= cancel(-7x)cancel(+7x)#
#rArr12x+12>=0# subtract 12 from both sides.
#12xcancel(+12)cancel(-12)>=0-12#
#rArr12x>= -12# To solve for x, divide both sides by 12
#(cancel(12) x)/cancel(12)>= (-12)/12#
#rArrx>= -1" is the solution"#