How do you solve #5x ^ { 2} + 60x + 180= 0#?

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Answer 1 · 2017-01-02T16:38:51

#x=-6#

#5x²+60x+180=0#

Divide all terms by #5#.

#x²+12x+36=0#

Factorise.

#x²+6x+6x+36=0#

#x(x+6)+6(x+6)=0#

#(x+6)(x+6)=0#

#x+6=0#

#x=-6#