How do you solve #5x - 23= - 10x + 47#?

1 Answer
Jim G.
Jan 27, 2017

#x=14/3#

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

add 10x to both sides.

#5x+10x-23=cancel(-10x)cancel(+10x)+47#

#rArr15x-23=47#

add 23 to both sides.

#15xcancel(-23)cancel(+23)=47+23#

#rArr15x=70#

To solve for x, divide both sides by 15

#(cancel(15) x)/cancel(15)=70/15#

#rArrx=70/15=14/3#

#color(blue)"As a check"#

Substitute this value into the equation and if the left side equals the right side then it is a solution.

#"left side "=(5xx14/3)-23=70/3-69/3=1/3#

#"right side "=(-10xx14/3)+47=-140/3+141/3=1/3#

#rArrx=14/3" is the solution"#

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