First, subtract the necessary values from each side of the equation to isolate the xx terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:
5x + 3 - color(red)(3x) - color(blue)(3) = 7 + 3x - color(red)(3x) - color(blue)(3)5x+3−3x−3=7+3x−3x−3
5x - color(red)(3x) + 3 - color(blue)(3) = 7 - color(blue)(3) + 3x - color(red)(3x)5x−3x+3−3=7−3+3x−3x
5x - color(red)(3x) + 0 = 7 - color(blue)(3) + 05x−3x+0=7−3+0
5x - 3x = 7 - 35x−3x=7−3
Next, we can combine like terms:
(5 - 3)x = 4(5−3)x=4
2x = 42x=4
Now we can solve for xx while keeping the equation balanced:
(2x)/color(red)(2) = 4/color(red)(2)2x2=42
(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 2
x = 2
