How do you solve $5x - 3+ x = 3x - 2- 1$ ?

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Answer 1 · 2017-07-03T15:04:26

See a solution process below:

First, group and combine like terms on each side of the equation:

$5x + x - 3 = 3x - 2 - 1$

$5x + 1x - 3 = 3x - 2 - 1$

$(5 + 1)x - 3 = 3x + (-2 - 1)$

$6x - 3 = 3x + (-3)$

$6x - 3 = 3x - 3$

Next, add $color(red)(3)$ and subtract $color(blue)(3x)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$-color(blue)(3x) + 6x - 3 + color(red)(3) = -color(blue)(3x) + 3x - 3 + color(red)(3)$

$(-color(blue)(3) + 6)x - 0 = 0 - 0$

$3x = 0$

Now, divide each side of the equation by $color(red)(3)$ to solve for $x$ :

$(3x)/color(red)(3) = 0/color(red)(3)$

$(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 0$

$x = 0$

How do you solve 5x - 3+ x = 3x - 2- 15x - 3+ x = 3x - 2- 1?