How do you solve #5x + 4= 7+ 2x#?

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Answer 1 · 2018-01-25T12:19:14

See a solution process below:

First, subtract #color(red)(4)# and #color(blue)(2x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#5x - color(blue)(2x) + 4 - color(red)(4) = 7 - color(red)(4) + 2x - color(blue)(2x)#

#(5 - color(blue)(2))x + 0 = 3 + 0#

#3x = 3#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = 3/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 1#

#x = 1#