How do you solve #-5x + 40x + 8= - 27#?

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Answer 1 · 2018-01-26T14:55:21

See a solution process below:

First, combine the like terms on the left side of the equation:

#-5color(red)(x) + 40color(red)(x) + 8 = -27#

#(-5 + 40)color(red)(x) + 8 = -27#

#35color(red)(x) + 8 = -27#

Next, subtract #color(red)(8)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#35x + 8 - color(red)(8) = -27 - color(red)(8)#

#35x + 0 = -35#

#35x = -35#

Now, divide each side of the equation by #color(red)(35)# to solve for #x# while keeping the equation balanced:

#(35x)/color(red)(35) = -35/color(red)(35)#

#(color(red)(cancel(color(black)(35)))x)/cancel(color(red)(35)) = -1#

#x = -1#