How do you solve $5 x - 6 + 2 x = 15 - 9 + 3 x$ $5x - 6+ 2x = 15- 9+ 3x$ ?

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Answer 1 · 2016-11-13T22:43:30

$x = 3$ $x = 3$

Step 1) Combine like terms on each side of the equation:

$(5 x + 2 x) - 6 = (15 - 9) + 3 x$ $(5x + 2x) - 6 = (15 - 9) + 3x$

$(5 + 2) x - 6 = 6 + 3 x$ $(5 + 2)x - 6 = 6 + 3x$

$7 x - 6 = 6 + 3 x$ $7x - 6 = 6 + 3x$

Step 2) solve for $x$ $x$ on one side of the equation while keeping the equation balanced:

$7 x - 6 + 6 - 3 x = 6 + 3 x + 6 - 3 x$ $7x - 6 + 6 - 3x= 6 + 3x + 6 - 3x$

$7 x - 3 x = 6 + 6$ $7x - 3x = 6 + 6$

$(7 - 3) x = 12$ $(7 - 3)x = 12$

$4 x = 12$ $4x = 12$

$\frac{4 x}{4} = \frac{12}{4}$ $(4x)/4 = 12/4$

$x = 3$ $x = 3$

How do you solve 5x - 6+ 2x = 15- 9+ 3x5x−6+2x=15−9+3x5x - 6+ 2x = 15- 9+ 3x?