How do you solve #-5x + 7= 2x - 63#?

1 Answer
Jul 28, 2017

See a solution process below:

Explanation:

Step 1) Add #color(red)(5x)# and #color(blue)(63)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#color(red)(5x) - 5x + 7 + color(blue)(63) = color(red)(5x) + 2x - 63 + color(blue)(63)#

#0 + 70 = (color(red)(5) + 2)x - 0#

#70 = 7x#

Step 2) Divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:

#70/color(red)(7) = (7x)/color(red)(7)#

#10 = (color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7))#

#10 = x#

#x = 10#