How do you solve 5x = y + 6 and 2x - 3y = 4 using substitution?

x=14/13 ; y=-8/13
$y = 5 x - 6$ Substituting y in equation $2 x - 3 y = 4$ we get $2 x - 3 \left(5 x - 6\right) = 4 \mathmr{and} 2 x - 15 x + 18 = 4 \mathmr{and} - 13 x = - 14 \mathmr{and} x = \frac{14}{13} \therefore y = 5 \cdot \frac{14}{13} - 6 \mathmr{and} y = - \frac{8}{13}$[Ans]