How do you solve #5x + y = 8# and #–4x – 4y = – 16# using substitution?
So always when you try to solve systems, if you find either a single y or x then use the substitution, just something I always do. Anyway so here we have
And in the first one we have a single y ( shown below)
Now we re-write it to get:
Put this equation :
into the other to get:
Divide 16 on both sides to get:
Now put that into any equation to get:
Simplify to get
Now check you work by putting in the numbers into the other equation to get:
So it's right with
Hope this helps!