How do you solve #5y-5=10#?
1 Answer
May 12, 2018
Explanation:
#"isolate "5y" by adding 5 to both sides of the equation"#
#5ycancel(-5)cancel(+5)=10+5#
#rArr5y=15#
#"divide both sides by 5"#
#(cancel(5) y)/cancel(5)=15/5#
#rArry=3#
#(5xx3)-5=15-5=10larr"Check"#
