How do you solve #-5y - 5( - 6- 2y ) = 0#?

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Answer 1 · 2016-09-24T10:41:04

#y = - 6#

We have: #- 5 y - 5 (- 6 - 2 y) = 0#

Let's expand the parentheses:

#=> - 5 y + 30 + 10 y = 0#

Let's collect the like terms:

#=> 5 y + 30 = 0#

We can now subtract both sides of the equation by #30#:

#=> 5 y = - 30#

Finally, to solve for #y#, let's divide both sides by #5#:

#=> y = - 6#

Therefore, the solution to the equation are #y = - 6#.