First, subtract #color(red)(5y)# and #color(blue)(6)# from each side of the inequality to isolate the #y# term while keeping the inequality balanced:
#-color(red)(5y) + 5y - 8 - color(blue)(6) < -color(red)(5y) + 7y + 6 - color(blue)(6)#
#0 - 14 < (-color(red)(5) + 7)y + 0#
#-14 < 2y#
Now, divide each side of the inequality by #color(red)(2)# to solve for #y# while keeping the inequality balanced:
#-14/color(red)(2) < (2y)/color(red)(2)#
#-7 < (color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2))#
#-7 < y#
To state the solution in terms of #y# we can reverse or "flip" the entire inequality:
#y > -7#
