How do you solve #6( 1- 4y ) = 18#?

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Answer 1 · 2016-09-18T13:12:22

#y = - (1) / (2)#

We have: #6 (1 - 4 y) = 18#

First, let's divide both sides of the equation by #6#:

#=> 1 - 4 y = 3#

Then, let's subtract #1# from both sides:

#=> - 4 y = 2#

Finally, to solve for #y#, let's divide both sides by #- 4#:

#=> y = - (1) / (2)#