Question

How do you solve `6+ ( 15\div 5+ 3) \times 1^ { 2}`?

Answer 1

12

Explanation:

To do this, we'll use the Order of Operations, known by some as PEMDAS.

First up is the P - Parenthesis (also known as Brackets). Within the bracket there is division and addition - so we do the division first:

`6+(15-:5+3)xx1^2`

`6+(3+3)xx1^2`

`6+(6)xx1^2`

Next up is E - Exponentials (`1^2=1` so it isn't much of one but we'll do it anyway):

`6+(6)xx1`

And now we have addition and multiplication left. The multiplication goes first:

`6+(6)xx1=6+6=12`