# How do you solve #(6- 2+ 2) \times 6#?

##### 1 Answer

Oct 6, 2016

#### Explanation:

When evaluating calculations with

#color(blue)"mixed operations"# we have to evaluate them in a particular order.Evaluate in the order set out in PEMDAS.

#6-2+2=4+2=6larr" bracket first"#

#=6xx6larr" multiplication next"#

#rArr(6-2+2)xx6=36#