How do you solve #(6- 2+ 2) \times 6#?

1 Answer
Jim G.
Oct 6, 2016

#36#

Explanation:

When evaluating calculations with #color(blue)"mixed operations"# we have to evaluate them in a particular order.

Evaluate in the order set out in PEMDAS.

#6-2+2=4+2=6larr" bracket first"#

#=6xx6larr" multiplication next"#

#rArr(6-2+2)xx6=36#

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