# How do you solve 6/2=4/p?

Oct 8, 2017

$p = 1 \frac{1}{3}$

#### Explanation:

$\frac{6}{2} = \frac{4}{p}$

multiply all terms by $20 p$

$\frac{6}{2} \setminus \times \left(20 p\right) = \frac{4}{p} \setminus \times \left(20 p\right)$

$\frac{6}{\cancel{2}} ^ 1 \setminus \times \left({\cancel{20}}^{10} p\right) = \frac{4}{\cancel{p}} \setminus \times \left(20 \cancel{p}\right)$

$60 p = 80$

Divide both sides by 60:

$\frac{60 p}{60} = \frac{80}{60}$

$\frac{\cancel{\left(60\right) \setminus \times p}}{\cancel{60}} = {\cancel{80}}^{4} / {\cancel{60}}^{3}$

$p = \frac{4}{3} = 1 \frac{1}{3}$

$p = 1 \frac{1}{3}$