How do you solve #6( 2b + 5) = - ( 3b - 15)#?

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Answer 1 · 2016-10-21T08:31:16

#b=-1#

#6(2b+5)=-(3b-15)#

Open the brackets on both sides. Keep in mind that two minus signs make a plus.

#12b+30=-3b+15#

Add #3b# to both sides.

#15b+30=15#

Subtract 30 from each side.

#15b=15-30#

#15b=-15#

Divide both sides by #15#.

#b=-1#