How do you solve #6- 2k = 4#?

Question

716 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-12T21:55:03

#=>k = 1#

We start with

#6-2k=4#

We subtract #6# from both sides

#cancel6-2k cancel(- 6) = 4-6#

#-2k = -2#

We divide both sides by #-2#

#(cancel(-2)k)/(cancel(-2)) = (-2)/(-2)#

#=>k = 1#