How do you solve #-6( 2n + 4) = 6- 6n#?

1 Answer
Nov 18, 2016

#n=-5#

Explanation:

Equation: #-6(2n+4)=6-6n#

Distribute left side #rArr -6(2n)+(-6(4))=6-6n#

Simplify distribution #rArr -12n+(-24)=6-6n#

Add #6n# to each side #rArr -12n\color(red)(+6n)+(-24)=6\cancel(-6n)\cancel(\color(red)(+6n))#

Subtract #(-24)# from each side #rArr -12n+6n\cancel(+(-24))\cancel(\color(indianred)(-(-24)))=6\color(indianred)(-(-24))#

Subtracting a negative number means adding the positive form #rArr -12n+6n=6+24#

Simplify like terms #rArr -6n=30#

Divide each side by #-6# to isolate the #n# #rArr (\cancel(\color(teal)(-6))n)/(\cancel(\color(teal)(-6)))=30/\color(teal)(-6)#

Solution: #n=-5#