How do you solve #|6- 2x | = 2| x - 3|#?
1 Answer
Nov 25, 2016
This equation is an identity, so true for any value of
Explanation:
Any positive scalar factor can be moved outside the
So we find:
#abs(6-2x) = abs(2(3-x)) = 2abs(3-x) = 2abs(x-3)#
for any value of
The solution space is the whole of
