How do you solve 6^ { 2x } + 6^ { x + 1} - 16= 0?
1 Answer
Sep 4, 2017
See explanation.
Explanation:
The equation is:
6^(2x)+6^(x+1)-16=0
This can be transformed to:
6^(2x)+6*6^x-16=0
Now if we replace
t^2+6t-16=0
This equation can be solved using the quadratic formula:
Now we have to find the values of
6^{x_1}=-8
This equation has no solution. There is no real value of
6^{x_2}=2
The only solutin of the exponential equation is