Question

How do you solve `6( 3^ { 4f - 2} ) = 2`?

Answer 1

Solution : `f=1/4`

Explanation:

`6(3 ^(4f-2))=2 or (3 ^(4f-2))=2/6`, taking log on both

sides we get `(4f-2) log3 = log(1/3)` or

`(4f-2) log 3 =log3^(-1)` or

`(4f-2) cancellog 3 =- cancellog3` or

`(4f-2) = -1 or 4f = 2-1 or 4f = 1 :. f =1/4`

Solution : `f=1/4` [Ans]