How do you solve #-6(3+6x)-6=-258#?

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Answer 1 · 2016-12-14T20:19:18

Step 1) Expand the terms in parenthesis:

#(-6*3) + (-6*6x) - 6 = -258#

#-18 - 36x - 6 = - 258#

Step 2) Combine like terms:

#-24 - 36x = - 258#

Step 3) Isolate the #x# term on one side of the equation while keeping the equation balanced:

#-24 + 24 - 36x = -258 + 24#

#0 - 36x = -234#

#-36x = -234#

Step 4) Solve for #x# while keeping the equation balanced:

#(-36x)/-36 = (-234)/-36#

#(cancel(-36)x)/cancel(-36) = 6.5#

#x = 6.5#