How do you solve #6( 3n + 2) \geq 6( 2- 6n ) + 4n#?

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Answer 1 · 2016-09-24T11:25:20

#n>=0#

We need to rearrange this equation to get #c >=# something. For the purpose of rearranging, we can treat the #>=# sign as an #=# sign.

First we expand the brackets;

#6(3n + 2) >= 6(2-6n) + 4n to#

#18n + 12 >= 12 - 36n + 4n # which is

#18n + 12 >= 12 - 32n#

Then we add #32n# to both sides

#50n + 12 >= 12#

Then we take #12# from both sides

#50n >= 0#

Finally we divide both sides by #50#

#n>=0#