How do you solve #6- 3t = t - 10#?

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Answer 1 · 2017-07-16T00:58:06

See a solution process below:

First, add #color(red)(3t)# and #color(blue)(10)# to each side of the equation to isolate the #t# term while keeping the equation balanced:

#6 - 3t + color(red)(3t) + color(blue)(10) = t - 10 + color(red)(3t) + color(blue)(10)#

#6 + color(blue)(10) - 3t + color(red)(3t) = t + color(red)(3t) - 10 + color(blue)(10)#

#16 - 0 = 1t + color(red)(3t) - 0#

#16 = (1 + color(red)(3))t#

#16 = 4t#

Now, divide each side of the equation by #color(red)(4)# to solve for #t# while keeping the equation balanced:

#16/color(red)(4) = (4t)/color(red)(4)#

#4 = (color(red)(cancel(color(black)(4)))t)/cancel(color(red)(4))#

#4 = t#

#t = 4#