How do you solve $6*4^(9x+1)=21$ ?

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Answer 1 · 2016-11-22T05:41:13

$x~=-0.01070$

$6*4^(9x+1)=21$

$4^(9x+1)=21/6=7/2$

$4^(9x) xx 4 =7/2$

$4^(9x) = 7/8$

$9xlog4 = log(7/8) = log7 - log8$

$9x = (log7-log8)/log4$

$9x ~= -0.09632$

$x~= -0.01070$

How do you solve 6*4^(9x+1)=216*4^(9x+1)=21?