How do you solve #6(4 h + 7) + 2( h - 5) - ( h - 11) = 18#?

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Answer 1 · 2016-09-16T03:31:00

#h=-1#

The mnemonic PEMDAS is helpful in answering this question as it helps us to remember the order of operations when solving complex math problems.

#6(4h+7)+2(h-5)-(h-11)=18#

Simplify #-(h-11)# to #-h+11#

The contents of the two remaining parentheses cannot be simplified further, and there are no exponents. So we start with multiplication.

Expand the terms in parentheses by multiplying the number in front by the terms inside the parentheses, moving from left to right.

#6xx4h+42+2h-10-h+11=18#

Group like terms.

#24h+2h-h+42-10+11=18#

Combine like terms.

#25h+43=18#

Subtract #43# from both sides.

#25h=18-43#

Simplify.

#25h=-25#

Divide both sides by #25#.

#h=(-25)/25#

Simplify.

#h=-1#