How do you solve #-6( 4- x ) = 12x#?

1 Answer
May 25, 2018

Answer:

#x = -6#

Explanation:

#-6(4-x)=12x#

First, we want to simplify #-6(4-x)# using the distributive property:
cdn.virtualnerd.com

Following this image, we know it becomes:
#color(blue)(-6(4-x) = (-6 * 4) + (-6 * -x) = -24 + 6x)#

Let's put that back into the equation:
#-24 + 6x = 12x#

Now subtract #color(blue)(6x)# from both sides of the equation:
#-24 + 6x quadcolor(blue)(-quad6x) = 12x quadcolor(blue)(-quad6x)#

#-24 = 6x#

Now divide both sides by #color(blue)6#:
#-24/color(blue)6 = (6x)/color(blue)6#

#-6 = x#

Therefore,
#x = -6#

Hope this helps!