How do you solve #6( 5x + 4) + 3( 6x + 3) + 6= 48x + 40#?

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Answer 1 · 2016-09-24T13:20:14

There are no values of #x# that fulfil this equation.

The aim is to rearrange the equation to get #x=# something.

First we multiply out brackets;

#6(5x +4) + 3(6x + 3) + 6 = 48x + 40 to#

#30x + 24 + 18x + 9 + 6 = 48x + 40#

Then we gather like terms

#48x + 39 = 48x + 40#

Finally we take #48x# from both sides to get

#39 != 40#