How do you solve #6-6(4r- 5)=-6-6(3r-1)#?

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Answer 1 · 2016-03-01T17:57:29

#color(green)( r = 6#

#6 - 6 (4r -5) = -6 - 6(3r-1)#

#6 - 6 * (4r) + (-6) * (-5) = -6 - 6 * (3r) + (-6) * (-1)#

#6 - 24r+ 30 = -cancel6 - 18r+ cancel6#

# - 24r+ 36 = - 18r#

# - 24r+ 18r = - 36#

# - 6r = - 36#

# r =( - 36)/ -6#

#color(green)( r = 6#