Question

How do you solve `6+ 6a = - 10+ 8a`?

Answer 1

`a=8`

Explanation:

Collect terms in a to one side of the equation and numeric values to the other side.

subtract 8a from both sides.

`6+6a-8a=-10cancel(+8a)cancel(-8a)`

`rArr6-2a=-10`

subtract 6 from both sides.

`cancel(6)cancel(-6)-2a=-10-6`

`rArr-2a=-16`

To solve for a, divide both sides by - 2

`(cancel(-2) a)/cancel(-2)=(-16)/(-2)`

`rArra=8" is the solution"`