How do you solve #-6- 7( 1- 2a ) = - 125#?

1 Answer
May 3, 2017

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis by multiplying each term in parenthesis by the term outside the parenthesis:

#-6 - color(red)(7)(1 - 2a) = -125#

#-6 - (color(red)(7) * 1) - (color(red)(-7) * 2a) = -125#

#-6 - 7 - (-14a) = -125#

#-13 + 14a = -125#

Next, add #color(red)(13)# to each side of the equation to isolate the #a# term while keeping the equation balanced:

#color(red)(13) - 13 + 14a = color(red)(13) - 125#

#0 + 14a = -112#

#14a = -112#

Now, divide each side of the equation by #color(red)(14)# to solve for #a# while keeping the equation balanced:

#(14a)/color(red)(14) = -112/color(red)(14)#

#(color(red)(cancel(color(black)(14)))a)/cancel(color(red)(14)) = -8#

#a = -8#