How do you solve #6( j - 5) = - 18#?

1 Answer
smendyka
Apr 7, 2017

See the entire solution process below:

Explanation:

First, divide each side of the equation by #color(red)(6)# to eliminate the outer term on the left side of the equation while keeping the equation balanced:

#(6(j - 5))/color(red)(6) = -18/color(red)(6)#

#(color(red)(cancel(color(black)(6)))(j - 5))/cancel(color(red)(6)) = -3#

#j - 5 = -3#

Now, add #color(red)(5)# to each side of the equation to solve for #j# while keeping the equation balanced:

#j - 5 + color(red)(5) = -3 + color(red)(5)#

#j - 0 = 2#

#j = 2#

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