Question

How do you solve `6^n=99`?

Answer 1

I got: `n=2.56458`

Explanation:

I would try taking the log in base `6` of both sides:
`log_6(6^n)=log_6(99)`
we get (using the definition of log):
`n=log_6(99)`
the log is tricky but if we have a calculator we can evaluate it after changing its base, say, to get a natural log in base `e` indicated as `ln`. So we get:
`n=ln(99)/(ln(6))=2.56458`