How do you solve #-6( x + 1) + 4= 27- 8x#?

1 Answer
Apr 13, 2018

#x = 14.5# or #14 1/2#

Here's how I did it:

Explanation:

#-6(x+1)+4=27-8x#

The first thing we want to do is distribute #-6(x+1)#:
#-6 * x = -6x#

#-6 * 1 = -6#

Now let's put these back into the equation:
#-6x - 6 + 4 = 27 - 8x#

Simplify the left side:
#-6x - 2 = 27 - 8x#

Now add #color(red)(8x)# to both sides of the equation:
#-6x - 2 quadcolor(red)(+quad8x) = 27 - 8x quadcolor(red)(+quad8x)#

#2x - 2 = 27#

Now add #color(red)2# to both sides of the equation:
#2x - 2 quadcolor(red)(+quad2) = 27 quadcolor(red)(+quad2)#

#2x = 29#

Divide both sides by #color(red)2#:
#(2x)/color(red)2 = 29/color(red)2#

#x = 14.5# or #14 1/2#

Hope this helps!