How do you solve #6( x - 1) + 4( 3x - 2) = 32#?

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Answer 1 · 2018-05-05T08:14:00

#x=2 5/9#

First expand the equation to get

#6(x - 1) + 4(3x - 2 ) = 32#

#6x - 6 + 12x -8 = 32#

Collect the like terms together to obtain

#6x + 12x -6 -8 = 32#

you get

# 18x -14 = 32#

#18x = 32 +14#

#18x = 46#

#x = 23/9#