How do you solve $-6(x-2) + 3x = -3(x+3)+21$ ?

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Answer 1 · 2018-07-25T21:31:37

All real $x$ i.e. $x\in \mathbb R$

Given that

$-6(x-2)+3x=-3(x+3)+21$

$-6x+12+3x=-3x-9+21$

$-3x+12=-3x+12$

The above equation holds for all real $x$

How do you solve -6(x-2) + 3x = -3(x+3)+21-6(x-2) + 3x = -3(x+3)+21?