Question

How do you solve `-6(x-2) + 3x = -3(x+3)+21`?

Answer 1

All real `x` i.e. `x\in \mathbb R`

Explanation:

Given that

`-6(x-2)+3x=-3(x+3)+21`

`-6x+12+3x=-3x-9+21`

`-3x+12=-3x+12`

The above equation holds for all real `x`