# How do you solve #62^(x+3) <= 7^(2x+1)#?

##### 2 Answers

take the common logarithm of both sides and you will get:

using the power rule for logs, the exponents become factors or multipliers and the equation reduces to:

by expanding , we will obtain a simple linear equation with 1 variable (x):

xlog62 + 3log62

collect all your x terms on one side of the equation and the others on the opposite side:

xlog62 - 2xlog7

factoring the common factor of 'x':

x(log62 - 2log7)

and the result is:

x

If you prefer:

#### Explanation:

You could use any form of log for this. I chose

Taking logs of both sides

Dividing the right hand side gives

Multiply by (-1)