How do you solve #-6j + 11= - 13- 8j#?

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Answer 1 · 2018-03-10T02:50:16

j = -12

-6j+11+8j=-13

2j+11=-13

2j=-11-13

2j=-24

divide by 2

-24/2 = -12

Answer 2 · 2018-03-10T02:51:01

See a solution process below:

FIrst, subtract #color(red)(11)# and add #color(blue)(8j)# to each side of the equation to isolate the #j# term while keeping the equation balanced:

#-6j + color(blue)(8j) + 11 - color(red)(11) = -13 - color(red)(11) - 8j + color(blue)(8j)#

#(-6 + color(blue)(8))j + 0 = -24 - 0#

#2j = -24#

Now, divide each side of the equation by #color(red)(2)# to solve for #j# while keeping the equation balanced:

#(2j)/color(red)(2) = -24/color(red)(2)#

#(color(red)(cancel(color(black)(2)))j)/cancel(color(red)(2)) = -12#

#j = -12#