# How do you solve 6m+n=9 and m-8n=26 using substitution?

$m = 2$
$n = - 3$

#### Explanation:

From the given equations
$6 m + n = 9$ first equation
$m - 8 n = 26$second equation

$m = 26 + 8 n$
insert the equivalent in the first equation

$6 m + n = 9$ first equation
$6 \left(26 + 8 n\right) + n = 9$ first equation
$156 + 48 n + n = 9$
$49 n = 9 - 156$
$49 n = - 147$
$n = - \frac{147}{49}$
$n = - 3$

Solve for m now using $n = - 3$ and $m = 26 + 8 n$

$m = 26 + 8 n$
$m = 26 + 8 \left(- 3\right)$
$m = 26 - 24$
$m = 2$

check:using the original equations
$6 m + n = 9$ first equation
$6 \left(2\right) + \left(- 3\right) = 9$ first equation

$12 - 3 = 9$
$9 = 9$

$m - 8 n = 26$second equation
$2 - 8 \left(- 3\right) = 26$second equation
$2 + 24 = 26$
$26 = 26$

God bless....I hope the explanation is useful.