How do you solve #6n - 4= 4n#?

Question

650 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-15T19:03:59

See a solution process below:

First, add #color(red)(4)# and subtract #color(blue)(4n)# from each side of the equation to isolate the #n# term while keeping the equation balanced:

#6n - 4 = 4n#

#-color(blue)(4n) + 6n - 4 + color(red)(4) = -color(blue)(4n) + 4n + color(red)(4)#

#(-color(blue)(4) + 6)n - 0 = 0 + color(red)(4)#

#2n = 4#

Now, divide each side of the equation by #color(red)(2)# to solve for #n# while keeping the equation balanced:

#(2n)/color(red)(2) = 4/color(red)(2)#

#(color(red)(cancel(color(black)(2)))n)/cancel(color(red)(2)) = 2#

#n =2#