How do you solve #6p - (5p +5) = -8 -2(p +12)#?

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Answer 1 · 2016-10-08T18:19:49

#p=-9#

#6p-(5p+5)=-8-2(p+12)#

#6p-5p-5=-8-2p-24#

#p-5=-2p-32#

#p+2p=-32+5#

#3p=-27#

#(cancel(3)p)/cancel(3)=-27/3#

#p=-9#