How do you solve #-6v + 3( v - 2) = 18#?

1 Answer
Jan 14, 2018

See a solution process below:

Explanation:

First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

#-6v + color(red)(3)(v - 2) = 18#

#-6v + (color(red)(3) xx v) - (color(red)(3) xx 2) = 18#

#-6v + 3v - 6 = 18#

Next, combine like terms on the left side of the equation:

#(-6 + 3)v - 6 = 18#

#-3v - 6 = 18#

Then, add #color(red)(6)# to each side of the equation to isolate the #v# term while keeping the equation balanced:

#-3v - 6 + color(red)(6) = 18 + color(red)(6)#

#-3v - 0 = 24#

#-3v = 24#

Now, divide each side of the equation by #color(red)(-3)# to solve for #v# while keeping the equation balanced:

#(-3v)/color(red)(-3) = 24/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))v)/cancel(color(red)(-3)) = -8#

#v = -8#