First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:
#-6v + color(red)(3)(v - 2) = 18#
#-6v + (color(red)(3) xx v) - (color(red)(3) xx 2) = 18#
#-6v + 3v - 6 = 18#
Next, combine like terms on the left side of the equation:
#(-6 + 3)v - 6 = 18#
#-3v - 6 = 18#
Then, add #color(red)(6)# to each side of the equation to isolate the #v# term while keeping the equation balanced:
#-3v - 6 + color(red)(6) = 18 + color(red)(6)#
#-3v - 0 = 24#
#-3v = 24#
Now, divide each side of the equation by #color(red)(-3)# to solve for #v# while keeping the equation balanced:
#(-3v)/color(red)(-3) = 24/color(red)(-3)#
#(color(red)(cancel(color(black)(-3)))v)/cancel(color(red)(-3)) = -8#
#v = -8#