How do you solve # 6x^{2} = 21x#?

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Answer 1 · 2016-09-13T07:29:03

#x = 0 or x = 7/2#

Start by dividing by 3 to make the equation as simple as possible.

#6x^2 = 21x " "rarr" " 2x^2 = 7x#

It is a quadratic #(x^2)# so make it equal to 0.

#2x^2 -7x = 0" " larr # now find factors

#x(2x-7)-0#

Let each factor be equal to 0.

#x = 0#

If # 2x-7=0 rarr x= 7/2#