How do you solve 6x^2+5=2x^2+1?

Sep 10, 2016

There is no real solution for $x$

Explanation:

Usually we would make a quadratic equation equal to 0.
However this example is a special case because there is no term in $x$

Re-arrange to give:

$6 {x}^{2} - 2 {x}^{2} = 1 - 5$

$4 {x}^{2} = - 4 \text{ } \leftarrow$ alarm bells should start ringing!

${x}^{2} = - 1$

This equation cannot be solved using real numbers because we cannot find the square root of a negative number.

To continue requires using complex numbers...