How do you solve #6x-3=4x+7#?

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Answer 1 · 2016-08-11T07:19:38

#x=5#

#6x-3=4x+7#

Add minus #-4x# on both sides

#6x-3-4x=4x+7-4x#
#6x-3-4x=cancel(4x)+7cancel(-4x)#
#2x-3=7#

Add #+3# to both sides

#2x-3+3=7+3#

#2xcancel(-3)cancel(+3)=7+3#

#2x=10#

Divide both sides by #2#

#(2x)/2=10/2#

#(cancel2x)/cancel2=10/2#

#x=5#