How do you solve #6x + 3< 5x - 1#?

1 Answer
Jim G.
Sep 26, 2016

#x<-4#

Explanation:

We can solve in a similar way to solving equations.

Have the x terms on the left and numeric values on the right.

subtract 5x from both sides of the inequation.

#6x-5x+3< cancel(5x)cancel(-5x)-1#

#rArrx+3< -1#

To solve for x, subtract 3 from both sides.

#xcancel(+3)cancel(-3) <-1-3#

#rArrx<-4" is the solution"#

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