# How do you solve -6y - 2x = 0 and 11y + 3x = 4 using substitution?

Jan 5, 2017

$x = - 6 \mathmr{and} y = 2$

#### Explanation:

$- 6 y - 2 x = 0 \to - 6 y = 2 x$
Therefore $- 3 y = x$

We can substitute $\textcolor{b l u e}{- 3 y = x}$ into the second equation;

$11 y + 3 \textcolor{red}{\left(x\right)} = 4$
$11 y + 3 \textcolor{red}{\left(- 3 y\right)} = 4$

This is simplified to;

$11 y - 9 y = 4$
$2 y = 4$
$y = 2$

As we know that $\textcolor{b l u e}{- 3 y = x}$, we can substitute the value of $y$ into that to get $x$

$- 3 y = x \to - 3 \left(2\right) = x$

$- 6 = x$